Question

3Xelevada a las dos + X-5= 2X elevada a las dos-2X+5

Answer 1

$3x^{2} +x - 5 = 2 x^{2} -2x +5$

$3x^{2} - 2 x^{2} +x +2x -5 - 5 = 0$

$x^{2} + 3x - 10 = 0$
x                       + 5
x                       - 2

(x+5)(x-2) = 0

x+5 = 0       x- 2 = 0
x = - 5         x = 2

CS = (-5; 2)