Question

(3x²-2x+5)+(x²+x-8)=
(3x²-2x+5)-(x²+x-8)=
(x-2) (x²+2x+4)=
(2x³-7x⁴-4x-12)÷(2x-1)=​

Answer 1

Respuesta:

$(3x^{2} -2x+5)+(x^{2} +x-8)=4x^{2} -x - 3\\(3x^{2} -2x+5)-(x^{2}+x-8) =2x^{2}-3x+13\\\\(x-2)(x^{2} +2x +4) = x^3 +2x^2 + 4x -2x^2-4x -8 = x^3 - 2$

Explicación paso a paso: