Question

(3x) + (4x) =
(–3x) + (4x) =
(3m) + (4m2) + (4n) =
(2b2 + 4c + 3a3) + (5a + 3b + c2) =
(3x) + (–4x) =
(–3x) + (–4x) =
(2x) + (2x2) =
(–2x) + (2x2) =
(2x) + (–2x2) =
(–2x) + (–2x2) =
(–3m) + (4m2) + (4n) =
(–3m) + (–4m2) + (4n) =
(–3m) + (4m2) + (–4n) =
(–2b2 + 4c + 3a3) + (5a + 3b – c2) =
(2b2 + 4c – 3a3) + (5a + 3b – c2) =
(2b2 – 4c + 3a3) + (5a + 3b + c2) =
(2b2 + 4c + 3a3) + (–5a + 3b + c2) =
ayudaa​

Answer 1

Respuesta:

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