Question

(3x+2) (x+y-z)- (3x-2)- (x4y-1) (3x+2)

Answer 1

Respuesta:

Forma simplificada

$-3x^{5}y-2x^{4}y+3xy-3xz+3x^{2}+2y-2z+2x+4$

Explicación paso a paso:

Distribuyes

$(3x+2)(x+y-z)-(3x-2)-(x^{4}y-1)(3x+2)$

$3x(x+y-z)+2(x+y-z)-(3x-2)-(x^{4}y-1)(3x+2)$

Distribuyes

$3x(x+y-z)+2(x+y-z)-(3x-2)-(x^{4}y-1)(3x+2)$

Distribuyes

$3x^{2}+3xy-3xz+2x+2y-2z-3x+2-(x^{4}y-1)(3x+2)$

$3x^{2}+3xy-3xz+2x+2y-2z-3x+2-(y(3x+2).x^{4}-1(3x+2))$

vuelves a distribuir

$3x^{2}+3xy-3xz+2x+2y-2z-3x+2-(3yx^{5}+2yx^{4}-1(3x+2)$

Distribuyes

$3x^{2}+3xy-3xz+2x+2y-2z-3x+2-3yx^{5}+2yx^{4}+3x+2)$

sumas los números

$3x^{2}+3xy-3xz+2x+2y-2z-3x+4-3yx^{5}+2yx^{4}+3$

$3x^{2}+3xy-3xz+2x+2y-2z+4-3yx^{5}+2yx^{4}$

Reordenas los términos

$-3yx^{5}-yx^{4}+3x^{2}+xy-3xz+2x+2y-2z+4$

Resultado

$-3x^{5}y-2x^{4}y+3xy-3xz+3x^{2}+2y-2z+2x+4$