Question

(3x+1)/(x^2-2x+4) =(x+14)/(x^3+8) + 3/(x+2)

Answer 1

Explicación paso a paso:

$\frac{3x + 1}{{x}^{2} - 2x + 4} = \frac{x + 14}{ {x}^{3} + 8} + \frac{3}{x + 2}$

$\frac{3x + 1}{ {x}^{2} - 2x + 4 } = \frac{x + 14}{(x + 2)( {x}^{2} - 2x + 4) } + \frac{3}{x + 2}$

(x + 2)(3x + 1) = (x + 14) + 3(x² - 2x + 4)

3x² + 6x + x + 2 = x + 14 + 3x² - 6x + 8

6x + 6x = 14 + 8 - 2

12x = 20

x = 20/12

x = 5/3