Question

3senxseny+5cosxcosy=0 caclular E=cos(x-y)/cos(x+y)

Answer 1

3senxseny+5cosxcosy=0  ; E=cos(x-y)/cos(x+y)

3senxseny= -5cosxcosy

(senxseny)/(cosxcosy)= -5/3

por teoría : si a/b=d/c ⇒(a+b)/(a-b)=(d+c)/(d-c)

(senxseny+cosxcosy)/(senxseny-cosxcosy)= (-5+3)/(-5-3)

cos(x-y)/-cos(x+y)=1/4

cos(x-y)/cos(x+y)= -1/4

AUTOR: SmithValdez