Question

(3rs-2t)²= (t-√3)= b) (2r ‒ 5)(2r ‒ 7) = c) (t ‒ 5)(t + 1.5) = d) (3s2 + 5)(3s2 ‒ 2) = e) (0.2x + 5y)(0.2x + 3y) = g) (x + 499)(x + 1) = ayudaaaa doy coronita y mis puntos :/​

Answer 1

Respuesta:

(3rs - 2t)² = (3rs)² - 2(3rs)(2t) + (2t)²

               = 9r²s² - 12rst + 4t²

(t - √3) = t - 1.73

(2r ‒ 5)(2r ‒ 7) = (2r)² - 14r - 10r + 35

                        = 4r² - 24r + 35

(t ‒ 5)(t + 1.5) = t² + 1.5t - 5t - 7.5

                     = t² - 3.5t - 7.5

(3s² + 5)(3s² ‒ 2) = (3s²)² - 6s² + 15s² - 10

                           = 9s⁴ + 9s² - 10

(0.2x + 5y)(0.2x + 3y) = (0.2x)² + (5y + 3y)(0.2x) + (5)(3)

                                   = 0.04x² + 1.6xy + 15

(x + 499)(x + 1) = x² + (499 + 1)x + (499)(1)

                        = x² + 500x + 499