Question

3mnx² - 2x +3mny²-2y

ayuda ;^;​

Answer 1

1. En general, dado a{x}^{2}+bx+cax2+bx+c, la forma factorizada es:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a})a(x−2a−b+√b2−4ac)(x−2a−b−√b2−4ac)

2. En este caso, a=3mna=3mn, b=-2b=−2 y c=3mn{y}^{2}-2yc=3mny2−2y.

3mn(x-\frac{2+\sqrt{{(-2)}^{2}-4\times 3mn(3mn{y}^{2}-2y)}}{2\times 3mn})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times 3mn(3mn{y}^{2}-2y)}}{2\times 3mn})3mn(x−2×3mn2+√(−2)2−4×3mn(3mny2−2y))(x−2×3mn2−√(−2)2−4×3mn(3mny2−2y))

3. Simplifica.

3mn(x-\frac{2+2\sqrt{1-3mny(3mny-2)}}{6mn})(x-\frac{2-2\sqrt{1-3mny(3mny-2)}}{6mn})3mn(x−6mn2+2√1−3mny(3mny−2))(x−6mn2−2√1−3mny(3mny−2))

4. Extrae el factor común 22.

3mn(x-\frac{2(1+\sqrt{1-3mny(3mny-2)})}{6mn})(x-\frac{2-2\sqrt{1-3mny(3mny-2)}}{6mn})3mn(x−6mn2(1+√1−3mny(3mny−2)))(x−6mn