Question

3logx-log32 = 2log x/2
responder
doy corona

Answer 1

Respuesta:

$3\log _{10}\left(x\right)-\log _{10}\left(32\right)=\frac{2\log _{10}\left(x\right)}{2}$

$3\log _{10}\left(x\right)\cdot \:2-\log _{10}\left(32\right)\cdot \:2=\frac{2\log _{10}\left(x\right)}{2}\cdot \:2$

$x=10^{\frac{5\log _{10}\left(2\right)}{2}}$

Dame las gracias , por favor