Question

3f+4(f-10)=f+20
por fa ayuda​

Answer 1

Respuesta:

f=10

Explicación paso a paso:

Solve for f:

3 f + 4 (f - 10) = f + 20

4 (f - 10) = 4 f - 40:

(4 f - 40) + 3 f = f + 20

Grouping like terms, 4 f + 3 f - 40 = (3 f + 4 f) - 40:

((3 f + 4 f) - 40) = f + 20

3 f + 4 f = 7 f:

7 f - 40 = f + 20

Subtract f from both sides:

(7 f - f) - 40 = (f - f) + 20

7 f - f = 6 f:

6 f - 40 = (f - f) + 20

f - f = 0:

6 f - 40 = 20

Add 40 to both sides:

6 f + (40 - 40) = 40 + 20

40 - 40 = 0:

6 f = 20 + 40

20 + 40 = 60:

6 f = 60

Divide both sides of 6 f = 60 by 6:

(6 f)/6 = 60/6

6/6 = 1:

f = 60/6

The gcd of 60 and 6 is 6, so 60/6 = (6×10)/(6×1) = 6/6×10 = 10:

Answer: |

| f = 10