35 pts.!!! Urge, por favor con procedimiento
[ 1/4 + 3/2 (4/5)] ÷ [ 3/4 ( -1/2) -1/6]
[ 5/4 + 14/8 (-2/4)²] ÷ [ 6/6 - 9/2 (-1/3)³]
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Hola!
35 pts.!!! Urge, por favor con procedimiento
[ 1/4 + 3/2 (4/5)] ÷ [ 3/4 ( -1/2) -1/6]
[ 5/4 + 14/8 (-2/4)²] ÷ [ 6/6 - 9/2 (-1/3)³]
![\left[ \dfrac{1}{4}+ \dfrac{3}{2} \left( \dfrac{4}{5}\right)\right]: \left[ \dfrac{3}{4}\left(- \dfrac{1}{2}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{1}{4}+ \dfrac{3*4}{2*5} \right]: \left[ \left(- \dfrac{3*1}{4*2}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{1}{4}+ \dfrac{12}{10} \right]: \left[ \left(- \dfrac{3}{8}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{10+48}{40} \right]: \left[ \dfrac{-9-4}{24} \right]=](https://tex.z-dn.net/?f=%0A%5Cleft%5B++%5Cdfrac%7B1%7D%7B4%7D%2B++%5Cdfrac%7B3%7D%7B2%7D+%5Cleft%28++%5Cdfrac%7B4%7D%7B5%7D%5Cright%29%5Cright%5D%3A++%5Cleft%5B+%5Cdfrac%7B3%7D%7B4%7D%5Cleft%28-++%5Cdfrac%7B1%7D%7B2%7D%5Cright%29+-++%5Cdfrac%7B1%7D%7B6%7D+%5Cright%5D%3D++%5C%5C++%5C%5C++%5C%5C+%5Cleft%5B++%5Cdfrac%7B1%7D%7B4%7D%2B++%5Cdfrac%7B3%2A4%7D%7B2%2A5%7D+%5Cright%5D%3A++%5Cleft%5B+%5Cleft%28-++%5Cdfrac%7B3%2A1%7D%7B4%2A2%7D%5Cright%29+-++%5Cdfrac%7B1%7D%7B6%7D+%5Cright%5D%3D++%5C%5C++%5C%5C++%5C%5C++%5Cleft%5B++%5Cdfrac%7B1%7D%7B4%7D%2B++%5Cdfrac%7B12%7D%7B10%7D+%5Cright%5D%3A++%5Cleft%5B+%5Cleft%28-++%5Cdfrac%7B3%7D%7B8%7D%5Cright%29+-++%5Cdfrac%7B1%7D%7B6%7D+%5Cright%5D%3D+++%5C%5C++%5C%5C++%5C%5C+%5Cleft%5B++%5Cdfrac%7B10%2B48%7D%7B40%7D+%5Cright%5D%3A++%5Cleft%5B++%5Cdfrac%7B-9-4%7D%7B24%7D+%5Cright%5D%3D "\left[ \dfrac{1}{4}+ \dfrac{3}{2} \left( \dfrac{4}{5}\right)\right]: \left[ \dfrac{3}{4}\left(- \dfrac{1}{2}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{1}{4}+ \dfrac{3*4}{2*5} \right]: \left[ \left(- \dfrac{3*1}{4*2}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{1}{4}+ \dfrac{12}{10} \right]: \left[ \left(- \dfrac{3}{8}\right) - \dfrac{1}{6} \right]= \\ \\ \\ \left[ \dfrac{10+48}{40} \right]: \left[ \dfrac{-9-4}{24} \right]=")
![\left[ \dfrac{58}{40} \right]: \left[ \dfrac{-13}{24} \right]= \dfrac{58*24}{40*(-13) } =\dfrac{1392}{-520 } = \boxed{- \dfrac{174}{65}}](https://tex.z-dn.net/?f=%5Cleft%5B++%5Cdfrac%7B58%7D%7B40%7D+%5Cright%5D%3A++%5Cleft%5B++%5Cdfrac%7B-13%7D%7B24%7D+%5Cright%5D%3D+%5Cdfrac%7B58%2A24%7D%7B40%2A%28-13%29+%7D++%3D%5Cdfrac%7B1392%7D%7B-520+%7D++%3D++%5Cboxed%7B-+%5Cdfrac%7B174%7D%7B65%7D%7D "\left[ \dfrac{58}{40} \right]: \left[ \dfrac{-13}{24} \right]= \dfrac{58*24}{40*(-13) } =\dfrac{1392}{-520 } = \boxed{- \dfrac{174}{65}}")
![\left[ \dfrac{5}{4}+ \dfrac{14}{8}\left( \dfrac{2}{4}\right) ^2\right] :\left[ \dfrac{6}{6}- \dfrac{9}{2}\left( \dfrac{1}{3}\right) ^3\right]= \\ \\ \\ \left[ \dfrac{5}{4}+ \dfrac{14}{8}\left( \dfrac{4}{16}\right)\right] :\left[ \dfrac{6}{6}- \dfrac{9}{2}\left( \dfrac{1}{27}\right)\right]= \\ \\ \\ \left[ \dfrac{5}{4}+ \dfrac{7}{16}\right] :\left[ \dfrac{6}{6}- \dfrac{1}{6}\right]= \dfrac{27}{16} : \dfrac{5}{6}= \dfrac{27*6}{16*5}= \boxed{ \dfrac{81}{40}}](https://tex.z-dn.net/?f=%5Cleft%5B++%5Cdfrac%7B5%7D%7B4%7D%2B++%5Cdfrac%7B14%7D%7B8%7D%5Cleft%28++%5Cdfrac%7B2%7D%7B4%7D%5Cright%29+%5E2%5Cright%5D+%3A%5Cleft%5B+%5Cdfrac%7B6%7D%7B6%7D-++%5Cdfrac%7B9%7D%7B2%7D%5Cleft%28+%5Cdfrac%7B1%7D%7B3%7D%5Cright%29+%5E3%5Cright%5D%3D++%5C%5C++%5C%5C++%5C%5C+%5Cleft%5B++%5Cdfrac%7B5%7D%7B4%7D%2B++%5Cdfrac%7B14%7D%7B8%7D%5Cleft%28++%5Cdfrac%7B4%7D%7B16%7D%5Cright%29%5Cright%5D+%3A%5Cleft%5B+%5Cdfrac%7B6%7D%7B6%7D-++%5Cdfrac%7B9%7D%7B2%7D%5Cleft%28+%5Cdfrac%7B1%7D%7B27%7D%5Cright%29%5Cright%5D%3D++%5C%5C++%5C%5C++%5C%5C++%5Cleft%5B++%5Cdfrac%7B5%7D%7B4%7D%2B++++%5Cdfrac%7B7%7D%7B16%7D%5Cright%5D+%3A%5Cleft%5B+%5Cdfrac%7B6%7D%7B6%7D-++%5Cdfrac%7B1%7D%7B6%7D%5Cright%5D%3D+++%5Cdfrac%7B27%7D%7B16%7D+%3A+%5Cdfrac%7B5%7D%7B6%7D%3D++%5Cdfrac%7B27%2A6%7D%7B16%2A5%7D%3D++%5Cboxed%7B+%5Cdfrac%7B81%7D%7B40%7D%7D+ "\left[ \dfrac{5}{4}+ \dfrac{14}{8}\left( \dfrac{2}{4}\right) ^2\right] :\left[ \dfrac{6}{6}- \dfrac{9}{2}\left( \dfrac{1}{3}\right) ^3\right]= \\ \\ \\ \left[ \dfrac{5}{4}+ \dfrac{14}{8}\left( \dfrac{4}{16}\right)\right] :\left[ \dfrac{6}{6}- \dfrac{9}{2}\left( \dfrac{1}{27}\right)\right]= \\ \\ \\ \left[ \dfrac{5}{4}+ \dfrac{7}{16}\right] :\left[ \dfrac{6}{6}- \dfrac{1}{6}\right]= \dfrac{27}{16} : \dfrac{5}{6}= \dfrac{27*6}{16*5}= \boxed{ \dfrac{81}{40}}")
Espero que te sirva, salu2!!!!
35 pts.!!! Urge, por favor con procedimiento
[ 1/4 + 3/2 (4/5)] ÷ [ 3/4 ( -1/2) -1/6]
[ 5/4 + 14/8 (-2/4)²] ÷ [ 6/6 - 9/2 (-1/3)³]
Espero que te sirva, salu2!!!!
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