Question

30 gramos de NaCI en 70 gramos de agua (d=1,10g/ml
Calcule la molaridad

Answer 1

PM (NaCl) = 23 + 35.45 = 58.45 g/mol

Volumen:
70g Agua x (1mL / 1.10 g) x (1L / 1000mL) = 0.064L

Moles:
30g NaCl x (1 mol / 58.45 g) = 0.5133 mol

*Molaridad (mol/L):
M = n / V
M = 0.5133 mol / 0.064 L --> [NaCl] = 8.02M