Question

3. Hallar f¹ (x), si f(x) = 4x - 3​

Answer 1

$f(x) \: = \: 4x \: - \: 3$

$y \: = \: 4x \: - \: 3$

$x \: = \: 4y \: - \: 3$

$4y \: - \: 3 \: = \: x$

$4y \: = \: x \: + \: 3$

$y \: = \: \frac{1}{4} x \: + \: \frac{3}{4}$

$\boxed{ \bold{ {f}^{ - 1}(x) \: = \: \frac{1}{4}x \: + \: \frac{3}{4} }}$