Question

3.55 DE BROMURO DE PLATA EN 65ML DE SOLUCIÓN

Answer 1

Respuesta:

M = 0.29 molar ≈ 3M

Explicación:

3.55 DE BROMURO DE PLATA EN 65 mL DE SOLUCIÓN

Mm NaBr: 187,77 g/mol

fórmula:

M = moles soluto (n)

             V(L)

1. Calcular volumen en litros

V = 65 / 1000

V = 0.065 L

2. Calcular moles de soluto

n = masa/Mm

n = 3.55 g / 187,77 g/mol

n = 0.0189 moles de soluto

3. calcular molaridad

M = 0.0189 moles

          0.065 L

M = 0.29 molar

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M = __masa__

       Mm x V(L)

M = _____3.55 g________

      187.77 g/mol x 0.065 L

M = 0.29 molar ≈ 3 M