Question

-3+{2x-5[(4x-1)-(x+3)]}=5x-8

Answer 1

-3+{2x-5{(4x-1)-(x+3)} = 5x-8
-3+{2x-5{4x-1-x-3} = 5x-8
-3+{2x-5(3x-4)} = 5x-8
-3+{2x-15x+20} = 5x-8
-3+{-13x+20} = 5x-8
-3-13x+20 = 5x-8
17-13x = 5x-8
-13x-5x = -17-8
-18x = -25
x = $\frac{-25}{-18}$ la fracción final es: $\frac{25}{18}$