Question

(×-3)(ײ+3×+9)-(×-1)(ײ+×+1)​

Answer 1

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$\left(x-3\right)\left(x^2+3x+9\right)-\left(x-1\right)\left(x^2+x+1\right)=-26$

$=x^3-27-\left(x-1\right)\left(x^2+x+1\right)$

$=x^3-27-x^3+1$

$=x^3-x^3-27+1$

$=-27+1$

$=-26$

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