Question

(2x³-7x²+8x-3)÷(x²-2x+1 ) ​

Answer 1

Respuesta:

la solución final es

$2x - 3$

Explicación:

(2x³-7x²+8x-3)÷(x²-2x+1)

$\frac{2x {}^{3} - 7x {}^{2} + 8x - 3}{x {}^{2} - 2x + 1 }$

$\frac{2x {}^{2} \times (x - 1) - 5x \times (x - 1) + 3(x - 1)}{(x - 1) {}^{2} }$

$\frac{(x - 1) \times (2x {}^{2} - 5x + 3) }{(x - 1) {}^{2} }$

$\frac{2x {}^{2} - 5x + 3 }{x - 1}$

$\frac{2x {}^{2} - 2x - 3x + 3}{x - 1}$

$\frac{2x \times (x - 1) - 3(x - 1)}{x - 1}$

$\frac{(x - 1) \times (2x - 3)}{x - 1}$

$2x - 3$

espero que te ayude