Question

2x2-4x+8 por formula general

Answer 1

SOLUCIÓN

♛ HØlα!! ✌

                   $Sea\:la\:ecuaci\'on\:cuadr\'atica:\\\\ax^2+bx+c=0\\\\Por\:f\'ormula\:general\:tenemos\:que:\\\\\\\mathrm{\boxed{x_{1,2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}}\\\\\\Del\:problema:\\\\\\a=2,b=-4,c=8\\\\\\ Entonces\:reemplazamos\\\\\\x_{1,2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x_{1,2}=\dfrac{-(-4)\pm \sqrt{(-4)^2-[4(2)(8)]}}{2(2)}\\\\\\x_{1,2}=\dfrac{4\pm \sqrt{16-(64)}}{4}\\\\\\x_{1,2}=\dfrac{4\pm \sqrt{-48}}{4}\\\\\\x_{1,2}=\dfrac{4\pm0}{4}$

                 

                 $\Rightarrow\:x_{1}=\dfrac{4+0}{4}\\\\\\x_{1}=\dfrac{4}{4}\\\\\\\boxed{\boldsymbol{x_{1}=1}}\\\\\\\Rightarrow\:x_{2}=\dfrac{4-0}{4}\\\\\\x_{2}=\dfrac{4}{4}\\\\\\\boxed{\boldsymbol{x_{2}=1}}$