Question

2x²+3y²=32
-3x²+4y²=-48​​

Answer 1

Respuesta:

2x²+2y²=32 and 3x²+3y²=48

x²+y²=16and x²+y²=16

if x²+y²=16,x+y=root of 16,x+y=4,x=4-y

x²+y²=16

(4-y)²+y²=16

16–8y+y²+y²=16,2y²-8y+16=16, 2y²-8y=16-16,2y²-8y=0

2y²-8y=0

2y(y-4)=0,y-4=0,y=4,Now y=4 value put in x=4-y so,

x=4-y

x=4–4

x=0

Explicación:

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