Question

2x²+3×-5=0 ayuda porfiis​

Answer 1

Respuesta:$x_{1} =1 ; x_{2} =-\frac{5}{2}$

Explicación paso a paso:

$2x^{2} +3x-5\\aplicamos formula general \\\frac{-b+/-\sqrt{b^{2} -4ac} }{2a} \\tomamos valores \\a=2\\b=3 \\c=-5\\reemplazamos\\\frac{-3+/-\sqrt{3^{2} -4(2)(-5)} }{2(2)}\\\frac{-3+/-\sqrt{9 -8(-5)} }{2(2)}\\\frac{-3+/-\sqrt{9 +40} }{4}\\ \frac{-3+/-\sqrt{49} }{4}\\x_{1}=\frac{-3+\sqrt{49} }{4} ; x_{2}=\frac{-3-\sqrt{49} }{4} \\ x_{1}=\frac{-3+7 }{4} ; x_{2}=\frac{-3-7 }{4}\\x_{1}=\frac{4 }{4} ; x_{2}=\frac{-10 }{4}\\x_{1} =1; x_{2} =-\frac{5}{2}$