Question

2x-1=5x+8... 3+3x-1=x+2+2x....2(1+2x)=10 ayudenmen porfaaa ​

Answer 1

Respuesta:

1)2x-1 = 5x+8

2x-5x = 8+1

-3x = 9

x = \frac{9}{-3}

−3

9

x = -3

2)3+3x-1 = x+2+2x

3x-x-2x = 2-3+1

0x = 0

3)2*(3x-2) = -2

6x-4 = -2

6x = -2+4

6x = 2

x = \frac{2}{6}

6

2

4)2*(1+2x) = 10

2+4x = 10

4x = 10-2

x = \frac{8}{4}

4

8

x = 2

5)\frac{1-x}{3}

3

1−x

= \frac{5x}{3}

3

5x

1-x = 5x

-x-5x = -1

-6x = -1

x = \frac{1}{6}

6

1

6)\frac{2x}{3}

3

2x

+ \frac{16}{3}

3

16

= \frac{-4x}{2}

2

−4x

\frac{2x}{3}

3

2x

+ \frac{4x}{2}

2

4x

= -\frac{16}{3}

3

16

\frac{4x+12x}{6}

6

4x+12x

= -\frac{16}{3}

3

16

\frac{16x}{6}

6

16x

= -\frac{16}{3}

3

16

16x = \frac{-96}{3}

3

−96

7)1 + \frac{1}{2}

2

1

*(4x-6) = -2

1 + 2x-3 = -2

2x = -2-1+3

2x = 0

x = 0

8)5-2*(1-x) = 2x-3

5-2+2x = 2x - 3

3+2x = 2x - 3

0x = -6 (esta ecuación es una incongruencia)

9)\frac{1}{2}

2

1

*(\frac{4x}{3}

3

4x

-4) = 0

\frac{4x}{6}

6

4x

-2 = 0

\frac{4x}{6}

6

4x

= 2

4x = 12

x = \frac{12}{4}

4

12

x = 3