2x-1=5x+8... 3+3x-1=x+2+2x....2(1+2x)=10 ayudenmen porfaaa
Respuestas a la pregunta
Respuesta:
1)2x-1 = 5x+8
2x-5x = 8+1
-3x = 9
x = \frac{9}{-3}
−3
9
x = -3
2)3+3x-1 = x+2+2x
3x-x-2x = 2-3+1
0x = 0
3)2*(3x-2) = -2
6x-4 = -2
6x = -2+4
6x = 2
x = \frac{2}{6}
6
2
4)2*(1+2x) = 10
2+4x = 10
4x = 10-2
x = \frac{8}{4}
4
8
x = 2
5)\frac{1-x}{3}
3
1−x
= \frac{5x}{3}
3
5x
1-x = 5x
-x-5x = -1
-6x = -1
x = \frac{1}{6}
6
1
6)\frac{2x}{3}
3
2x
+ \frac{16}{3}
3
16
= \frac{-4x}{2}
2
−4x
\frac{2x}{3}
3
2x
+ \frac{4x}{2}
2
4x
= -\frac{16}{3}
3
16
\frac{4x+12x}{6}
6
4x+12x
= -\frac{16}{3}
3
16
\frac{16x}{6}
6
16x
= -\frac{16}{3}
3
16
16x = \frac{-96}{3}
3
−96
7)1 + \frac{1}{2}
2
1
*(4x-6) = -2
1 + 2x-3 = -2
2x = -2-1+3
2x = 0
x = 0
8)5-2*(1-x) = 2x-3
5-2+2x = 2x - 3
3+2x = 2x - 3
0x = -6 (esta ecuación es una incongruencia)
9)\frac{1}{2}
2
1
*(\frac{4x}{3}
3
4x
-4) = 0
\frac{4x}{6}
6
4x
-2 = 0
\frac{4x}{6}
6
4x
= 2
4x = 12
x = \frac{12}{4}
4
12
x = 3