Question

2sen(2x+40°)=6/5
ayuden!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Respuesta:

2sen(2x+40°)=6/5

ayuden!!!!!!!!!!!!!!!!!!!!!!!!!

Explicación:

$2\sin \left(2x+40^{\circ \:}\right)=\frac{6}{5}\\\\\frac{2\sin \left(2x+40^{\circ \:}\right)}{2}=\frac{\frac{6}{5}}{2}\\\\\sin \left(2x+40^{\circ \:}\right)=\frac{3}{5}$

$2x+40^{\circ \:}=\arcsin \left(\frac{3}{5}\right)+360^{\circ \:}n,\:2x+40^{\circ \:}=180^{\circ \:}-\arcsin \left(\frac{3}{5}\right)+360^{\circ \:}n\\\\x=180^{\circ \:}n-20^{\circ \:}+\frac{\arcsin \left(\frac{3}{5}\right)}{2},\:x=180^{\circ \:}n+90^{\circ \:}-20^{\circ \:}-\frac{\arcsin \left(\frac{3}{5}\right)}{2}$

$x=180^{\circ \:}n-20^{\circ \:}+\frac{0.64350\dots }{2},\:x=180^{\circ \:}n+90^{\circ \:}-20^{\circ \:}-\frac{0.64350\dots }{2}$