Question

...................2n+1
si p(x) = (x-1) -3;hallar p(0) + p(1)

a)1 b)-1 c)0 d)-7 e)7

Answer 1

p(x)=(x-1)-3
p(0)=(0-1)-3=-1-3=-4
p(1)=(1-1)-3=0-3=-3
p(0)+p(1)=-4-3=-7