Question

(2n+1) (n+2) = 81
Calcular n

Answer 1

Respuesta:

(2n + 1)(n + 2) = 81

2n² + 4n + n + 2 = 81

2n² + 5n + 2 - 81 = 0

2n² + 5n - 79 = 0

n = -5 ± √25+4•2•79 / 2•2 =

= -5 ± √25+632 / 4

= -5 ± √657 / 4

= -5 ± √73•3² / 4

= -5 ± 3√73 / 4

n1 = (-5 + 3√73) /4

n2 = (-5 - 3√73) /4