Question

(2am+1) (-3am+2) ayúda ​

Answer 1

$\boxed{(2am+1) (-3am+2)}$

$\boxed{=(2m+1)((3-a)(m)(+2)}$

$\boxed{=(2am)((-3a)(m))+(2am(2+(1)(-3a)(m)+(+1)(2)}$

$\boxed{=-6a^{2} m^{2} +4am-3am+2 }$

$\boxed{ \boxed{ \boxed{-6a^{2}m^{2} am+2 } } }$