Question

{√27[(√12-√3)(√45-√20)]-√80}=​

Answer 1

Respuesta:

{√27[(√12-√3)(√45-√20)]-√80}

{√27[(√12-3)(√45-20)-√80}

{√27[(√9)(√25)]-√80}

{√27[3*5]-√80}

{√27*15-√80}

forma exacta: 7√30- 4√5

forma decimal: 29.39630711...