Question

√25 + 4 - 5 - 4^2 + 25 - ^3 √64
√36 + 8 - 12 + 2^2 - 21 - ^3 √125

Answer 1

$\sqrt{25} + 4 - 5 - 4^{2} + 25 - \sqrt[3]{64} \\\\5 + 4 - 5 - 16 + 25 - 4\\ \\5 +4+ 25 - 5 -16 - 4\\\\34 - 25\\\\9$:

$\sqrt{36} + 8 - 12 + 2^{2} - 21 - \sqrt[3]{125}\\\\6 + 8 - 12 + 4 - 21 - 5\\\\6+8+4 -12-21-5\\\\18 - 38\\\\-20$

Eternamente axllxa