Question

(20x3- 2 x 2 - 16x + 6) : (4x- 2) ayudaa UwU

Answer 1

Respuesta:

(20x3- 2 x 2 - 16x + 6) : (4x- 2)

$=\frac{40x+6}{4x-2}\\\\=\frac{2\left(20x+3\right)}{4x-2}\\\\=\frac{2\left(20x+3\right)}{2\left(2x-1\right)}\\\\=\frac{20x+3}{\left(2x-1\right)}\\\\=\frac{20x+3}{2x-1}$