Question

-2(y-1) + 44(y-1) - 5[y-2[4-y) + 3y] – [y+1)} = 2y - (-5-y)
Con procedimiento ​

Answer 1

-2(y-1) + 44(y-1) - 5[y-2[4-y) + 3y] – [y+1)} = 2y - (-5-y)

[-2(y)+(-2)(-1)]+[(44)(y)+(44)(-1)]-5{y-2[4-y+3y]-y+1}= 2y+5+y

-2y-3+44y-44-5{y-2[4+2y]-y+1}=3y+5

(-2y+44y)+(-3-44-5){(y)(4)+(y)(+2y)+(-2)(+4)+(-2)(+2y)-y+1=3y+5

42y-52{(4y+2y²-8-4y)(-y+1)=3y+5

43y-52{-4y²+4y-2y³+3y²+8y-8+4y²-4y}=3y+5

43y-52(-2y³+3y²+8y-8)=3y+5

aquí lo separaré por partes porque son muy largos:

(43y)(-2y³)+(43y)(+3y²)+(43y)(8y)+(43y)(-8)

=-86y⁴+129y³+344y²+344y-344

(-52)(-2y³)+(-52)(3y²)+(-52)(8y)+(-52)(-8)

=104y³-156y²-416y+416

ahora sumaré ambos resultados:

(-86y⁴+129y³+344y²+344y-344)+(104y³-156y²-416y+416)

-86y⁴+233y³+188y²-72y+72

-86y⁴+233y³+188y²-72y+72=3y+5

-86y⁴+233y³+188y²-72y-3y+72-5=0

-86y⁴+233y³+188y²-75y-67=0