Question

2. $\frac{c}{7}$ = $\frac{3}{4}$

$\frac{g+3}{4}$ + $\frac{4g}{5}$ = 5

$\frac{e-5}{9}$ = $\frac{e-25}{5}$

ayuda plz

Answer 1

1) 2 (c / 7) = 3 / 4

2c = 3 × 7 / 4

c = (21 / 4) / 2

c = 21 / 8

2) (g + 3) / 4 + 4g / 5 = 5

5g + 15 + 16g = 100

21g = 85

g = 85 / 21

3) (e - 5) / 9 = (e - 25) / 5

5e - 25 = 9e - 225

200 = 4e

50 = e