Question

2 potenciado a la n+4 +2 potenciado a la n+3 todo entre 2potenciado a la n+3 - 2 potenciado n+2

Answer 1

Explicación paso a paso:

$\frac{ {2}^{n + 4} + {2}^{n + 3} }{ {2}^{n + 3} - {2}^{n + 2} } \\ \\ = \frac{{2}^{n}( {2}^{4}) + {2}^{n}( {2}^{3})}{{2}^{n}( {2}^{3}) - {2}^{n}( {2}^{2})} \\ \\ = \frac{ {2}^{n} ( 1 + {2}^{4} + 1 + {2}^{3} ) }{{2}^{n} ( 1 + {2}^{3} - (1 + {2}^{2}))} \\ \\ = \frac{2 + 16 +8 }{8 - 4} \\ \\ = \frac{26}{4} \\ \\ = \frac{13}{2} = 6 \frac{1}{2}$