Question

2^(n+3)=40-2^(n+1)ayudenme por favor
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Answer 1

hola n=2

saludos

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Answer 2

2^(n+3)=40-2^(n+1)

sumas en ambos lados "2^(n+1)"

2^(n+1)+2^(n+3)=40-2^(n+1)+2^(n+1)

queda

2^(n+1)+2^(n+3)=40

factorisas "2^(n+1)+2^(n+3)"

2^n+1(2^2+1)=40

2^n+1 (5) =40      el 5 pasa a dividir

2^n+1=8     >DESCOMPONE EL 8

2^n+1=2^3  

ECUACIÓN EXPONENCIAL

n+1=3

n=2 ======>RPTA