Question

2.- Hallar “X” mediante el teorema de Pitágoras ayudaaa​

Answer 1

Tenemos en cuenta principalmente la fórmula del teorema:

$h^{2} = C1^{2}+C2^{2}$

Entonces realizamos los cálculos:

1) C1 = 5 ; C2 = 12

$h^{2}=5^{2}+12^{2}\\h^{2}=25+144\\h=\sqrt{169}\\h=13$   X = 13

2) C1 = 15 ; C2 = 20

$h^{2}=15^{2}+20^{2}\\h^{2}=225+400\\h=\sqrt{625} \\h=25$ X = 25

3) C1 = 12 ; H = 20

$20^{2} = 12^{2} + C2^{2}\\400 = 144 + C2^{2}\\400-144 = C2^{2}\\\sqrt{256} = C2\\16 = C2$ X = 16

4) C1 = 15 ; H = 17

$17^{2} = 15^{2} + C2^{2}\\289 = 225 + C2^{2}\\289 - 225 = C2^{2}\\\sqrt{64} = C2\\8 = C2$X = 8

$Dudas$ $o$ $consultas$ $en$ $los$ $comentarios.$