Question

2 elevado a (x+1) mas 2 elevado a (x) mas 2 elevado a(x-1) =28

Answer 1

Resolvemos.

$2^{x+1} + 2^{x} + 2^{x-1} = 28$

$2^{x-1}( 2^{2}+ 2^{1} +1) =28$

$2^{x-1}(7) = 28$

$2^{x-1} = \frac{28}{7}$

$2^{x-1} = 4$

Llevamos a bases iguales .

$2^{x-1} = ( 2^{2})$

Se va el "2".

$x - 1 = 2$

$x = 3$