Question

2.- Eleva al cuadrado los siguientes binomios:

i) (3a + 5b)² = ??
j) (2f - 5g)² = ??
k) (9h²-2h)²= ??
l) (-10x²+2y³)²=??
m) (-11m³-3m²)²=??
n) (10a²-5b³)²=??
ñ) (⅕f²+½f²)²=??
o) (⅖x³-¼y²)²=??

ayuda;-;​

Answer 1

Respuesta:

I) (3a + 5b)² = 9a² + 30ab + 25b²

j) (2f - 5g)² = 4f² - 20fg + 25g²

k) (9h² - 2h)² = 81h⁴ - 36h³ + 4h²

L) (-10x² + 2y³)² = 4y⁶ - 40x² y³ + 100x⁴

M) (-11m³ -3m²)² = 121m⁶ + 66m⁵ + 9m⁴

N) (10a² - 5b³)² = 100a⁴ - 100a²h³ + 25h⁶

Ñ) (⅕f² + ½f²)² = 49 f⁴

49 f⁴ 100

O) (⅖x³ - ¼y²)² = 4 x⁶ - 1 x³ y² 1 y⁴

25 5 16

Answer 2

Tenemos en cuenta la fórmula:

(a+b)2 = a² + 2ab + b²

(a-b)2 = a² - 2ab + b²

Resolvemos:

1.-

(3a + 5b)² = a² + 2ab + b²

(3a + 5b)² = (3a)² + 2(3a)(5b) + (5b)²

(3a + 5b)² = 9a + 30ab + 25b

2.-

(2f - 5g)² = a² - 2ab + b²

(2f - 5g)² = (2f)² - 2(2f)(5g) + (5g)²

(2f - 5g)² = 4f - 20fg + 25g

3.-

(9h²-2h)²= a² - 2ab + b²

(9h²-2h)²= (9h²)² - 2(9h²)(2h) + (2h)²

(9h²-2h)²= 81h⁴ - 36h²h + 4h

4.-

(-10x²+2y³)²= a² + 2ab + b²

(-10x²+2y³)²= (-10x²)² + 2(-10x²)(2y³) + (2y³)²

(-10x²+2y³)²= 100x⁴ - 40x²y³ + 4y⁶

5.-

(-11m³-3m²)² = a² - 2ab + b²

(-11m³-3m²)² = (-11m³)² - 2(-11m³)(-3m²) + (3m²)²

(-11m³-3m²)² = 121m⁶ + 66m³m² + 9m⁴

6.

(10a²-5b³)²= a² - 2ab + b²

(10a²-5b³)²= (10a²)² - 2(10a²)(-5b³) + (-5b³)²

(10a²-5b³)²= 100a⁴ - 100a²b³ + 25b⁶

7.-

(⅕f²+½f²)²= a² + 2ab + b²

(⅕f²+½f²)²= (⅕f²)² + 2(⅕f²)(½f²) + (½f²)²

(⅕f²+½f²)²= 1/25f⁴ + (⅖f²)(f²) + ¼f⁴

8.-

(⅖x³-¼y²)²= a² - 2ab + b²

(⅖x³-¼y²)²= (⅖x³)² - 2(⅖x³)(-¼y²) + (¼y²)²

(⅖x³-¼y²)²= 4/25x⁶ - (4/5x³)(-2/4y²) + 1/16y⁴

Miguel Gámez.