2. Determina la masa molecular de los siguientes compuestos:
a. KBr g. NaOH
b. Na2SO4 h. HCl
c. Pb(NO3)2 i. Ag2CO3
d. C2H5OH j. HClO
e. H2O2 k. BaCl2
f. Fe2O3 l. Mg(HCO3)2
Respuestas a la pregunta
Respuesta:
a. KBr g. NaOH
K = 1 x 39 = 39 g/mol Na: 1 x 23 = 23 g/mol
Br = 1 x 80 = 80 g/mol O: 1 x 16 = 16 g/mol
Mm = 119 g/mol H: 1 x 1 = 1 g/mol
Mm = 40 g/mol
Explicación:
. Determina la masa molecular de los siguientes compuestos:
a. KBr g. NaOH
b. Na2SO4 h. HCl
c. Pb(NO3)2 i. Ag2CO3
d. C2H5OH j. HClO
e. H2O2 k. BaCl2
f. Fe2O3 l. Mg(HCO3)2
a. KBr g. NaOH
K = 1 x 39 = 39 g/mol Na: 1 x 23 = 23 g/mol
Br = 1 x 80 = 80 g/mol O: 1 x 16 = 16 g/mol
Mm = 119 g/mol H: 1 x 1 = 1 g/mol
Mm = 40 g/mol
b. Na2SO4 h. HCl
Na: 2 x 23 = 46 g/mol H: 1 x 1 = 1 g/mol
S: 1 x 32 = 32 g/mol Cl: 1 x 35.5 = 35.5 g/mol
O: 4 x 16 = 64 g/mol
Mm = 142 g/mol
c. Pb(NO3)2 i. Ag2CO3
Pb: 1 x 207 = 207 g/mol Ag: 2 x 107 = 214 g/mol
N: 2 x 14 = 28 g/mol C: 1 x 12 = 12 g/mol
O: 6 x 16 = 96 g/mol O: 3 x 16 = 48 g/mol
Mm = 331 g/mol Mm = 274 g/mol
d. C2H5OH j. HClO
C: 2 x 12 = 24 g/mol H: 1 x 1 = 1 g/mol
H: 6 x 1 = 6 g/mol Cl: 1 x 35.5 = 35.5 g/mol
O: 1 x 16 = 16 g/mol O: 1 x 16 = 16 g/mol
Mm = 46 g/mol Mm = 52.5 g/mol
e. H2O2 k. BaCl2
H: 2 x 1 = 2 g/mol Ba = 1 x 137 = 137 g/mol
O: 2 x 16 = 32 g/mol Cl = 2 x 35.5 = 71 g/mol
Mm = 34 g/mol Mm = 208 g/mol
f. Fe2O3 l. Mg(HCO3)2
Fe: 2 x 56 = 112 g/mol Mg: 1 x 24 = 24 g/mol
O: 3 x 16 = 48 g/mol H: 1 x 2 = 2 g/mol
Mm = 160 g/mol C: 2 x 12 = 24 g/mol
O: 6 x 16 = 96 g/mol
Mm = 146 g/mol