Question

2.5g de etanol (C2H5OH)en 100ml de solucion

Answer 1

2.5 g de etanol (C2H5OH)en 100 ml de solucion

Mm C2H5OH = 46 g/mol

1. calcular moles

n = masa/Mm

n = 2.5 g / 46 g/mol

n = 0.054 moles

2. calcular el volumen en litros

V = 100 / 1000

V = 0.100 L

3. Calcular Molaridad

M = n soluto / V(L)

M = 0.054 moles / 0.100 L

M = 0.54 molar

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% m/v = (m soluto / v solc.) x 100

%m/v = (2.5 g / 100 mL) x 100

% m/v = 2.5 %