Question

2/5(5y-1)+3/10(10y-3)=1/2(y-2)-6/5

Answer 1

Respuesta:

$\frac{2}{5}\left(5y-1\right)+\frac{3}{10}\left(10y-3\right)=\frac{1}{2}\left(y-2\right)-\frac{6}{5}\quad :\quad y=-\frac{1}{5}\quad \left(\mathrm{Decimal}:\quad y=-0.2\right)$

Explicación paso a paso:

$\frac{2}{5}\left(5y-1\right)+\frac{3}{10}\left(10y-3\right)=\frac{1}{2}\left(y-2\right)-\frac{6}{5}\\desarollar \frac{2}{5}\left(5y-1\right)+\frac{3}{10}\left(10y-3\right)=5y-\frac{13}{10}\\ desarollar \frac{1}{2}\left(y-2\right)-\frac{6}{5}==-\frac{11}{5}+\frac{1}{2}y\\5y-\frac{13}{10}=-\frac{11}{5}+\frac{1}{2}y\\\mathrm{Sumar\:}\frac{13}{10}\mathrm{\:a\:ambos\:lados}\\5y-\frac{13}{10}+\frac{13}{10}=-\frac{11}{5}+\frac{1}{2}y+\frac{13}{10}\\5y=-\frac{9}{10}+\frac{1}{2}y$$\mathrm{Restar\:}\frac{1}{2}y\mathrm{\:de\:ambos\:lados}\\5y-\frac{1}{2}y=-\frac{9}{10}+\frac{1}{2}y-\frac{1}{2}y\\\\\frac{9}{2}y=-\frac{9}{10}\\\mathrm{Multiplicar\:ambos\:lados\:por\:}2\\2\cdot \frac{9}{2}y=2\left(-\frac{9}{10}\right)\\9y=-\frac{9}{5}\\\mathrm{Dividir\:ambos\:lados\:entre\:}9\\\frac{9y}{9}=\frac{-\frac{9}{5}}{9}\\y=-\frac{1}{5}$

saludos