Question

(2/3x^3y-1/4)(2/3x^3y+1/4)

Answer 1

PROCEDIMIENTO:

$(\frac{2}{3} x^{3} y-\frac{1}{4} )*\frac{2}{3}x^{3} y+\frac{1}{4} )\\\\(\frac{2}{3} x^{3} y)^{2} -(\frac{1}{4})^{2} \\\\\frac{4}{9} x^{6} y^{2} -\frac{1}{16}$

Resultado: $\\\frac{4}{9} x^{6} y^{2} -\frac{1}{16}$