Question

[-2+3x(2-5): 3]- [(3-5+2) -2 x (3-4) ]
ayudeme
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Answer 1

Respuesta:

$\left(\frac{-2+3x\left(2-5\right)}{3}\right)-\left(\left(3-5+2\right)-2x\left(3-4\right)\right)\\\\=\frac{-2+3x\left(2-5\right)}{3}-\left(\left(3-5+2\right)-2x\left(3-4\right)\right)\\\\=\frac{-2+3x\left(2-5\right)}{3}-\left(3-5+2-2x\left(3-4\right)\right)\\\\=\frac{-2-9x}{3}-2x\\\\=\frac{-2x\cdot \:3-2-9x}{3}\\\\=\frac{-6x-2-9x}{3}\\\\=\frac{-15x-2}{3}$

F<3