Question

2/3x(1/4x ^2-3/5x+2/7)
pliissssss

Answer 1

$\frac{2}{3x\left(\frac{1}{4}x^2-\frac{3}{5}x+\frac{2}{7}\right)}$

$\frac{1}{4}x^2=\frac{x^2}{4}$

$\frac{3}{5}x=\frac{3x}{5}$

$=\frac{2}{3x\left(\frac{x^2}{4}-\frac{3x}{5}+\frac{2}{7}\right)}$

$\frac{x^2}{4}-\frac{3x}{5}+\frac{2}{7}=\frac{35x^2-84x+40}{140}$

$=\frac{2}{3\cdot \frac{35x^2-84x+40}{140}x}$

$=\frac{2}{\frac{3x\left(35x^2-84x+40\right)}{140}}$

$=\frac{2\cdot \:140}{3x\left(35x^2-84x+40\right)}$

$=\frac{280}{3x\left(35x^2-84x+40\right)}$

¡Espero haberte ayudado Roseariko!