Question

(2-3i) - (5+4i)
(3+2i) (4-2i)
2+4i 4-2i
1+5i 3+41​

Answer 1

Si la i son "imaginarios" sería asi

A)

(2-3i)-(5+4i) = - 3-7i

2-3i-5-4i

-3-7i

B)

(3+2i)(4-2i) = 16+2i

3(42i+2i*14-2i)

12-6i+8i-41(-1)

16+2i

C)

2+4i*4-2i = 2+14i

2+16i-2i

2+14i

D)

1+5i*3+41 = 42+15i

1+15i+41