Question

2* { 3a^2b - [4ba^2-ab-(2bc-7a^2b)-(2ba-3bc)] + ab }


Con a = -2; b= 1/2 y c = -3

Answer 1

$(18/2)-4=5$

Sustituyendo a y aplicando algunas operaciones con a=-2:

$2* { 3(-2)^2b - [4b(-2)^2-(-2)b-(2bc-7(-2)b)-(2b(-2)-3bc)] + (-2)b }$

$2* { 12b -[16b+2b-(2bc+14b)-(-4b-3bc)]-2b}$

Sustituyendo b= 1/2 y aplicando algunas operaciones:  

$2* { 12(1/2)-[16(1/2)+2(1/2)-(2(1/2)c+14(1/2))-(-4(1/2)-3(1/2)c)]-2(1/2)}$

$2* {6-[8+1-(1c+7)-(-2-3(1/2)c)]-1}$

$2* [6-(9-1c-7+2+(3/2)c)-1]$

Sustituyendo c=-3 y aplicando algunas operaciones. :

$2* [6-(9-1(-3)-7+2+(3/2)(-3))-1]$

$2* [6-(9+3-7+2-(9/2))-1]$

$2* (6-9-3+7-2+(9/2)-1)=2*(-6+5+(9/2)-1)$

$2*(-6+5+(9/2)-1)=-12+10+(18/2)-2$

$2*(-6+5+(9/2)-1)=(18/2)-4$

$(18/2)-4=5$

a = -2

b= 1/2  

c = -3