Question

[2+3(2-5) +8]- [(3-5+2)7+(-8)

Answer 1

Respuesta:

9

Explicación paso a paso:

[2+3(2-5) +8]- [(3-5+2)7+(-8)

(2 + 3(-3) + 8) - [(-2 + 2)7 - 8)

(2 - 9 + 8)  -  (0 - 8)

  1   - (-8)

 1 + 8 = 9

Answer 2

$[2+3(2-5) +8]- [(3-5+2)7+(-8)$

$\lfloor 2+3\left(-3\right)+8\rfloor -\lfloor \left(3-5+2\right)\times 7-8\rfloor$

$\lfloor 2-9+8\rfloor -\lfloor \left(3-5+2\right)\times 7-8\rfloor$

$\lfloor 1\rfloor -\lfloor \left(3-5+2\right)\times 7-8\rfloor$

$1-\lfloor \left(3-5+2\right)\times 7-8\rfloor$

$1-\lfloor \left(-2+2\right)\times 7-8\rfloor$

$1-\lfloor 0-8\rfloor$

$1-\left(-8\right)$

$1 + 8 = 9$