Question

19ab + 18ab + 17ab ... 1ab= xyz77 hallar a+x​

Answer 1

$\overline{19ab}+\overline{18ab}+\overline{17ab}+\cdots+\overline{1ab}=\overline{xyz77}\\ \\(1900+\overline{ab})+(1800+\overline{ab})+(1700+\overline{ab})+\cdots+(100+\overline{ab})=\overline{xyz77}\\ \\100(19+18+17+\cdots+1)+19\times\overline{ab} =\overline{xyz77}\\\\19000+19\times\overline{ab} =\overline{xyz77}\\\\===============\\19\times\overline{ab} =...77\to b=3\\19\times\overline{a3} =...77\\19(10a+3)=...77\\190a+57=...77\\190a=...20\to a=8\\1520=...20\\===============$

$19000+19\times83 =\overline{xyz77}\\ \\20577=\overline{xyz77}\to x=2\\ \\a+x=8+2=10$

Answer 2

Respuesta:

Explicación paso a paso:

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