Matemáticas, pregunta formulada por maticito65, hace 16 días

18. Reduce a una sola potencia:

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Contestado por IvyChen
4

a) {a}^{5}   \times  {a}^{3}  =  {a}^{5 + 3}  =  {a}^{8}

b) {x}^{4}  \times  {x}^{4}  =  {x}^{4 + 4}  =  {x}^{8}

c) {x}^{2}  \times  {x}^{8}  =  {x}^{2 + 8}  =  {x}^{10}

d) {a}^{8}  \div  {a}^{5}  =  {a}^{8 - 5}  =  {a}^{3}

e) {x}^{6}  \div  {x}^{5}  =  {x}^{6 - 5}  = x

f) {( {a}^{3} )}^{2}  =  {a}^{3 \times 2}  =  {a}^{6}

g) {( {10}^{2} )}^{3}  =  {10}^{2 \times 3} =  {10}^{6}

h) {( {m}^{2} )}^{4}  =  {m}^{2 \times 4}  =  {m}^{8}

i) {( {5}^{4} )}^{2}  =  {5}^{4 \times 2}  =  {5}^{8}

j) {a}^{3}  \times  {a}^{4}  =  {a}^{3 + 4}  =  {a}^{7}

k) {a}^{6}  \div  {a}^{4}  =  {a}^{6 - 4}  =  {a}^{2}

l)( {a}^{8}  \div  {a}^{6} ) \times ( {a}^{6} \div  {a}^{5}  ) =  {a}^{8 - 6}  \times  {a}^{6 - 5}  =  {a}^{2}  \times a =  {a}^{2 + 1}  =  {a}^{3}

m)(  {x}^{3} \times  {x}^{5}  ) \div ( {x}^{2}  \times  {x}^{4} ) =  {x}^{3 + 5}  \div  {x}^{2 + 4}  =  {x}^{8}  \div  {x}^{6}  =  {x}^{ 8- 6}  =  {x}^{2}

n)( {a}^{2} \times  {a}^{3}   \times  {a}^{2} ) \div ( {a}^{5}  \times  {a}^{2} ) =  {a}^{2 + 3 + 2}  \div  {a}^{5 + 2}  =  {a}^{7}  \div  {a}^{7}  =  {a}^{7 - 7}  =   {a}^{0}  = 1

o) {( {x}^{2} )}^{3}  \div x =  {x}^{2 \times 3}  \div x =  {x}^{6}  \div x =  {x}^{6 - 1}  =  {x}^{5}

p) {( {m}^{3} )}^{2}  \div  {m}^{4}  =  {m}^{3 \times 2}  \div  {m}^{4}  =  {m}^{6}  \div  {m}^{4}  =  {m}^{6 - 4}   = {m}^{2}

q) {( {a}^{4} )}^{3}  \div  {( {a}^{3} )}^{3}  =  {a}^{4 \times 3}  \div  {a}^{3 \times 3}  =  {a}^{12}  \div  {a}^{9}  =  {a}^{12 - 9}  =  {a}^{3}

r) [ {( {a}^{3} )}^{2} \times  {( {a}^{2} )}^{4}  ]  \div  {( {a}^{5} )}^{2}  = ( {a}^{3 \times 2}  \times  {a}^{2 \times 4} ) \div   {a}^{5 \times 2}   = ( {a}^{6} \times  {a}^{8}  ) \div  {a}^{10}  =  {a}^{6 + 8}  \div  {a}^{10}  =  {a}^{14}  \div  {a}^{10}  =  {a}^{14 - 10}  =  {a}^{4}

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