Question

((17-4+2)+3+2x7-3)+([(15+6+2)+3+21+4+32÷5-4= ​

Answer 1

Hola!▪°▪

((17-4+2)+3+2x7-3)+([(15+6+2)+3+21+4+32÷5-4=

=13+2+3+(2×7)−3+15+6+2+3+21+4+32÷5−4

=15+3+(2×7)−3+15+6+2+3+21+4+32÷5−4

=18+(2×7)−3+15+6+2+3+21+4+32÷5−4

=18+14−3+15+6+2+3+21+4+32÷5−4

=32−3+15+6+2+3+21+4+32÷5−4

=29+15+6+2+3+21+4+32÷5−4

=29+21+2+3+21+4+32÷5−4

=29+23+3+21+4+32÷5−4

=29+26+21+4+32÷5−4

=29+47+4+32÷5−4

=29+51+32÷5−4

=29+287÷5−4

=29+267÷5

=412/5

kiy_.