Question

16-8×+4(×-6)=-(2×-3)+[-(×-1)+6]
Por favor alguien me ayude con esto. La tarea es para hoy

Answer 1

16-8x+4(x-6)=-(2x-3)+[-(x-1)+6]=
=16-8x+4x-24=-(2x-3)-(x-1)+6=
=16-4x-24=-(2x-3)-(x-1)+6=
=-8-4x=-(2x-3)-(x-1)+6=
=-8-4x=-2x-(-3)-(x-1)+6=
=-8-4x=-2x+3-(x-1)+6=
=-8-4x=-2x+3-x-(-1)+6=
=-8-4x=-2x+3-x+1+6=
=-8-4x=-3x+3+1+6=
=-8-4x=-3x+4+6=
=-8-4x=-3x+10=
=-8-4x+3x=10
=-8x-x=10
-x=10+8
-x=18
x=-18