Question

16×⁴-27y⁴-24ײy² entre 8×⁸-9y⁸+6×y²-12ײy​

Answer 1

Respuesta:

1)2⁵⁽²⁾ =  2¹⁰

2) 3⁴⁽³⁾ = 3¹²

3) a³⁽⁷⁾ = a²¹

4)x⁴⁽⁵⁾ = x²⁰

5) -(1)⁵x²⁽⁵⁾=  -x¹⁰

6) (-1)²x⁵⁽²⁾= x¹⁰

7) y²⁺⁵ = y⁷

8) x⁷⁺⁴ = x¹¹

9) a³⁻⁵ = a⁻² = 1/a²

10)  b⁻²⁺⁶ = b⁴

11) (3)²x²x⁻⁷ = 9x²⁻⁷= 9x⁻⁵ = 9/x⁵

12) (4)⁻²(x)⁻²x⁴ = (1/16)x⁻²⁺⁴ = (1/16)x² = x²/16

13) (2)²(x)²(2)³(x⁻¹)³ = 4x².8x⁻³ = 32x²⁻³ = 30x⁻¹ = 32/x

14) x³/2(4)²(x⁻¹)²= (x³/2)16x⁻² = 16/2.x³⁻² =  8x

15) (x²)³y³z³x⁴y⁴ = x⁶⁺⁴y³⁺⁴z³ = x¹⁰y⁷z³

16) 3²y²(z²)²(y³)³z³ = 9y²z⁴y⁹z³ = 9y²⁺⁹z⁴⁺³= 9y¹¹z⁷

17) (x⁻²)⁻²y⁻² = x⁴y⁻²=  x⁴/y²

18) a⁻¹(b⁻³)⁻¹ = a⁻¹b³ = b³/a

19) x⁻¹(y²)⁻¹(z³)⁻¹x³y³z³ = x⁻¹⁺³y⁻²⁺³z⁻³⁺³ = x²y

20) (x²)²p²(q²)²x⁻¹(p²)⁻¹= x⁴p²q⁴x⁻¹p⁻² = x⁴⁻¹p²⁻²q⁴ = x³q⁴

21) (2⁴)²/4²= 2⁴⁽²⁾/16 = 2⁸/2⁴ = 2⁸⁻⁴ = 2⁴ = 16

22) 3³⁽²⁾/3⁵ = 3⁶/3⁵ = 3⁶⁻⁵ = 3

23) (1/3)⁻²/3⁻⁴ = 3²/3⁻⁴= 3²⁻⁽⁻⁴⁾= 3⁶

24) 1/5³/5⁻²= 5⁻³/5⁻² = 5⁻³⁻⁽⁻²⁾ = 5⁻¹ =  1/5

25) x⁵⁻⁽⁻²⁾ = x⁵⁺² = x⁷

26) y⁻³⁻⁽⁻⁷⁾ = y⁻³⁺⁷ = y⁴

27) x²⁽³⁾/x⁴= x⁶/x⁴ = x⁶⁻⁴ = x²

28) z⁻⁸/z⁸ = z⁻⁸⁻⁸ = z⁻¹⁶ = 1/z¹⁶

29) a⁻¹²/a⁻¹² = a⁻¹²⁻⁽⁻¹²⁾ = a ⁻¹²⁺¹² = a⁰ = 1

30)b⁻¹⁴/b⁹ = b⁻¹⁴⁻⁹ = b⁻²³ =  1/b²³

31 ) (-1)²(x³)²/(-1)⁻³x⁻³ = x⁶/-x⁻³ = -x⁶⁻⁽⁻³⁾ = -x⁶⁺³ =  -x⁹

32) (-1)⁻³(y⁻¹)⁻³/(-1)⁻²(y²)⁻²= -y³/y⁻⁴ = -y³⁻⁽⁻⁴⁾ = -y³⁺⁴ = - y⁷

Explicación paso a paso:Espero te sirva