Question

12m²-13m-35=0 como sea resuelve? plis​

Answer 1

Respuesta:

m₁ = 7/3

m₂ = -5/4

Explicación paso a paso:

Usando formula resolvente

$m_{1;2} = \frac{-(-13)\pm\sqrt{(-13)^2-4*12*(-35)}}{2*12}\\\\m_{1;2} = \frac{13\pm\sqrt{169+1680}}{24}\\\\m_{1;2} = \frac{13\pm\sqrt{1849}}{24}\\\\m_{1;2} = \frac{13\pm43}{24}\\\\m_1 = \frac{13+43}{24}\qquad m_2= \frac{13-43}{24}\\\\m_1 = \frac{56}{24}\qquad \quad m_2= \frac{-30}{24}\\\\m_1 = \frac{7}{3} \qquad \qquad m_2= -\frac{5}{4}\\\\m_1 \approx 2,333 \qquad m_2 \approx -1,25$